HORSEPLOP.COM
General Category => Harness Racing => Topic started by: Poker King on April 24, 2019, 07:27:50 AM
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No doubt the time has come for the USTA to start measuring racetracks. Ever since the the MEADOWLANDS building was put on the other side of the track the races go 1 to 2 seconds faster than ever before and last quarters of 25 seconds is bogus. It’s time USTA!!!! Get off your asses and do something useful for all the money you collect. Show up unannounced and measure all 3 of Gural’s tracks because they are all 2 seconds faster than any other track out there!!! AND......... that’s with barring the drug trainers. Imagine if ALLARD raced there, the track record would be 1:44 ngc3 ngc3 ngc3 73cv.2 73cv.2 73cv.2
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Time .. dont mean shit. Only thing that matters is where you finish. You cant handicap off times, to many variables.
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Time .. dont mean shit. Only thing that matters is where you finish. You cant handicap off times, to many variables.
You absolutely can use times in handicapping but you have to have an accurate variant or else it's shit.
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In the paddock at Yonkers there was a discussion about time and someone, I don't remember who, was saying he would prefer a horse that won in 2:05 to one that got beat in 2:04. Herve said i'll take the one that got beat in 2:04 and walked out.
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Anyone can measure the length of any track via Google maps = just bring up the visual image of the track, then right click and select "Measure Distance" - and move/click the cursor around the inner periphery of the track.
I did the Meadowlands 10 times and came up with these distances in feet :
5216
5218
5222
5213
5204
5202
5214
5217
5215
5214
for an average of 5214' with a standard deviation of 6'.
But I was measuring exactly along the boundary with the turf course - all horses will be racing at least N feet away from that boundary and therefore will travel 2*pi*N additional feet beyond 5214.
For N=0, D = 5214'
For N=1, D = 5220'
For N=2, D = 5226'
For N=3, D = 5232'
For N=4, D = 5239'
For N=5, D = 5245'
For N=6, D = 5251'
For N=7, D = 5257'
For N=8, D = 5264'
For N=9, D = 5270'
For N=10,D = 5276'
For N=11,D = 5283'
I.e., any horse racing within 11 feet of the turf course boundary will travel slightly less than 1 mile.
These slightly shortened distances can be converted into times in seconds. For a 1:50 pacer
For N=0, t = 0.60
For N=1, t = 0.55
For N=2, t = 0.49
For N=3, t = 0.43
For N=4, t = 0.38
For N=5, t = 0.32
For N=6, t = 0.26
For N=7, t = 0.20
For N=8, t = 0.15
For N=9, t = 0.09
For N=10,t = 0.03
For N=11,t = -0.02
So horses racing about 3-7 feet away from the turf course boundary will have times that are about 1 to 2 fifths of a second too fast.
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Nice info but when was the last time a harness race in the USA was held on the turf ?
Turf course boundary where TBs used to run at M1 is what I was led to believe. Dunno...
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Nice info but when was the last time a harness race in the USA was held on the turf ?
Actually only a couple years ago at the meadowlands they had a Turf racing meet for standardbreds
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Standardbred racetracks are measured out from the hubrail, or where the hubrail should be. 3 ft I think ......
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Nice info but when was the last time a harness race in the USA was held on the turf ?
https://www.youtube.com/watch?v=50bakxBg7Aw